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- Review Usubstitutionap Calculus 3
- Review Usubstitutionap Calculus Pdf
- Review Usubstitutionap Calculus 1
- Review Usubstitutionap Calculus 2
Review Usubstitutionap Calculus 3
Section 1-3 : Trig Substitutions
For problems 1 – 8 use a trig substitution to eliminate the root.
Review Usubstitutionap Calculus Pdf
- (sqrt {4 - 9{z^2}} ) Solution
- (sqrt {13 + 25{x^2}} ) Solution
- ({left( {7{t^2} - 3} right)^{frac{5}{2}}}) Solution
- (sqrt {{{left( {w + 3} right)}^2} - 100} ) Solution
- (sqrt {4{{left( {9t - 5} right)}^2} + 1} ) Solution
- (sqrt {1 - 4z - 2{z^2}} ) Solution
- ({left( {{x^2} - 8x + 21} right)^{frac{3}{2}}}) Solution
- (sqrt {{{bf{e}}^{8x}} - 9} ) Solution
Review Usubstitutionap Calculus 1
Review Usubstitutionap Calculus 2
For problems 9 – 16 use a trig substitution to evaluate the given integral.
- ( displaystyle int{{frac{{sqrt {{x^2} + 16} }}{{{x^4}}},dx}}) Solution
- ( displaystyle int{{sqrt {1 - 7{w^2}} ,dw}}) Solution
- ( displaystyle int{{{t^3}{{left( {3{t^2} - 4} right)}^{frac{5}{2}}},dt}}) Solution
- ( displaystyle int_{{ - 7}}^{{ - 5}}{{frac{2}{{{y^4}sqrt {{y^2} - 25} }},dy}}) Solution
- ( displaystyle int_{1}^{4}{{2{z^5}sqrt {2 + 9{z^2}} ,dz}}) Solution
- ( displaystyle int{{frac{1}{{sqrt {9{x^2} - 36x + 37} }},dx}}) Solution
- ( displaystyle int{{frac{{{{left( {z + 3} right)}^5}}}{{{{left( {40 - 6z - {z^2}} right)}^{frac{3}{2}}}}},dz}}) Solution
- ( displaystyle int{{cos left( x right)sqrt {9 + 25 sin^2left( x right)} ,dx}}) Solution
AP Calculus AB > Unit 08 > 8.04 - Antidfferentation by Substitution (Day 2)-
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